Pythagoras Theorem
This video course introduces Pythagoras’ Theorem in a clear and student-friendly way, explaining the relationship between the sides of a right-angled triangle. Students learn to identify the hypotenuse and apply the formula through guided examples and practice questions.
Related Lessons:
Pythagoras Theorem
Here are the key points when applying the Pythagoras Theorem:
- Only applied to right-angle triangle
- The longest side of the right-angle triangle is directly opposite the right angle
- Squared of the longest side = sum of the squared of the 2 shorter sides
The Pythagoras Theorem formula is:
\(𝑐^2 = 𝑎^2+𝑏^2\)
Pythagoras Theorem Example 1
PQR is a triangle in which \(∠𝑃𝑄𝑅=90°\). Given that PR=3cm, \(QR=(3x)cm\) and \(PQ=(x+1)cm\),
- Form an equation in \(x\) and show that it reduces to \(5𝑥^2+𝑥−4=0\)
- Solve this equation and find the length of QR
Pythagoras Theorem Example 2
The shadow of a lamp post and that of a girl overlaps one another. The girl is 1.6m tall and her shadow DP is 6.4m long. The lamp post is 44.8m away from the girl. Given that triangle PAB is similar to triangle PCD, find
- the height of the lamp post.
- distance from the top of the lamp post to the girl’s head (Length of AC)
Pythagoras Theorem Example 3
In the figure, PQ is perpendicular bisector of the chord HK. If HK=3cm and PQ=3.2cm, calculate the radius of the circle.
Pythagoras Theorem Example 4
Given that AB=8cm, BC=6cm, AE=4cm and AD=DC, find the value of
- AD
- DE